(3b)
    h=7cm
    T=462cm^2
    T=pie sqr + 2 pie rH
    462= pie( r ^2 +2*7*r)
    462/3.142
    =r sqr= =14r
    r sqr+ 14r=147
    r sqr +14r- 147=0
    r= 14+-( (sqr(14))-4*1*147)/2*1
    r=-(14 +-(196-4))/2
    r=(-14+_12)/2
    r=(-14+12)/2 or
    r=2/2
    =1cm
    ==================================
    (4a)
    Pr(3)=x/total
    total=25+30+x+28+40+32
    =155+x
    0.225=x/155+ x
    =34.875+0.225x=x
    x-0.225x=34.875
    =0.775x=34.875 degree
    x=34.875/0.775
    =45
    (4b)
    Pr(even)=30+28+40+32
    =90
    Pr(even)=90/200=9/20
    Pr(prime no)=25=30+45+40
    =140
    Pr(prime no)=140/200=14/20
    Pr(even or prime)=9/20 + 14/20
    ===========================
    (5a)
    Area PSR=1/2*PR*SM
    PR=8+6=14cm
    36=1/2 * 14* 6
    36=1/2 * 14* 6 *QR
    QR=8.6cm
    (5b)
    diagram
    sin45 degree= 10.65/h
    h=10.65/sin 45 degree
    =10.65/0.7071
    h=15.06cm
    ===============================
    (6a)
    first term9a)=1.0=1
    common diff(d)=3-1=2
    last term(L)=101
    L=a+(n-1)d
    101=1+(n-1)*2
    (n-1)*2=100
    n-1=100/2
    n-1=50
    n=501+1
    n=51
    sum(s)=n/2(2a+(n-1)d)
    S=51/2(2*1+(51-1)*2)
    s=25.5(2+100)
    S=25.5*102=2601
    (6b)
    UC=95
    Bus & Train(B&T)=7
    Train & Car( T & C)=3
    B&T&C=8
    Bus only(x)=B&C only
    Bus(b)=47
    train(T)=30
    (draw the venn diagram)
    Bus only= 47-(7+8+x)
    x=47-15+x
    47=x+x+7+8
    47=2x+15
    2x=47-15
    2x=32
    x=32/2
    =16
    Train only= 30-(7+8+2)
    =30-18=12
    (6bi)=x=16
    (6bii)
    number who travelled by at leasttwo means
    =7+1+3+8
    =19
    ==================================
    (7a)
    given;
    (x-2)/4=(x+2)/2x
    2x*(x-2)=4*(x+2)
    2x^2 -4x= 4x+8
    2x^2-4x-4x-8=0
    2x^2-8x-8=0
    x^2-4x-4=0
    x^2-4x=4
    x^2-(4* 1/2)=4+(2)^2
    (x-2)^2=4+4
    (x-2)^2=8
    (x-2)= sqr root(8)
    x-2=+-2.83
    x=+-2.83
    x=+_2.83+2
    x=-2.83+2
    x=4.83 or x=-0.83
    (7b)
    P+Q+S=180 degree(sum of angles in a triangle)
    52 degree+ 90 degree+ S= 180 degree
    142+ S=180
    S=180-142
    S=38 degree
    (i)52+38+SQT
    =180 degree
    SQT=180-90
    SQT=90 degree
    (ii)PQT= 52 degree
    ==============================
    (8a)
    diagram
    z=110 degree(sum of angles on a straight line)
    z=180-110
    z=70 dgree
    w degree= 70 degree
    x+r+w degree= 180 degree(sum of angle in a triangle)
    x+2x+70 degree=180 degree
    3x=110
    x=110/3=36.7 dgeree
    (8b)
    B=10, G=12
    TB=600.00
    TB=TG+600
    mean of TB=100+ mean of TG
    where TB= total collection of boys
    TG=total collection by girls
    mean of TB= ET/B
    mean of TB= (TG+600)/10
    100+ mean of TG= (TG+600)/100
    mean of TG= mean of TG/12
    100+ mean of G/12= (TG+600)/10
    (100+TG)/12=(TG+600)/10
    10*(1200+TG)=12*(TG+600)
    =12000+10TG=12TG+7200
    =12TG-10TG=12000-7200
    2TG=4800
    TG=N2400
    TB=TG+600
    TB=600+2400
    Tb=N3000
    =============================
    (11a)
    Given (3p+4q)/(3p-4q) = 2
    3p+4q=2*(3p-4q)
    3p+4q=6p-8q
    3p-6p=-4q-8q
    =-3p=-12q
    p/q=-12/-3
    p/q=4/1, P=4, q=1
    p:q=4;1
    (11b)
    (i)
    perimeter(p)=PQ+PU+QR
    PQ=UT+TS+SR
    34=PQ+UR+4+4
    PQ=UR
    34-8=2PQ
    PQ=26/2=13cm
    (ii)
    13=2+TS+2
    TS=13-4=9cm
    radius(r)=9/2=4.5cm
    Area(A)= pie r sqr+22/7*(4.5)^2
    =445.5/7
    63.64cm^2
    MORE ANSWERS LOADING…….
    6a)
    Sn=n/2(2a+(n-1)d)
    A=1, d=2, n=n
    Sn=n/2(2*1+(n-1)2)
    N/2(2+2,-2)
    =n/2*2=n^2
    6b
    ========================================
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